(2v^2-9)/(v^2-v-6)

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Solution for (2v^2-9)/(v^2-v-6) equation: 


D( v )

v^2-v-6 = 0

v^2-v-6 = 0

v^2-v-6 = 0

v^2-v-6 = 0

DELTA = (-1)^2-(-6*1*4)

DELTA = 25

DELTA > 0

v = (25^(1/2)+1)/(1*2) or v = (1-25^(1/2))/(1*2)

v = 3 or v = -2

v in (-oo:-2) U (-2:3) U (3:+oo)

(2*v^2-9)/(v^2-v-6) = 0

v^2-v-6 = 0

v^2-v-6 = 0

DELTA = (-1)^2-(-6*1*4)

DELTA = 25

DELTA > 0

v = (25^(1/2)+1)/(1*2) or v = (1-25^(1/2))/(1*2)

v = 3 or v = -2

(v+2)*(v-3) = 0

(2*v^2-9)/((v+2)*(v-3)) = 0

2*v^2 = 9 // : 2

v^2 = 9/2

v^2 = 9/2 // ^ 1/2

abs(v) = (9/2)^(1/2)

v = (9/2)^(1/2) or v = -(9/2)^(1/2)

v in { (9/2)^(1/2), -(9/2)^(1/2) }

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